10x^2-12x+4=116

Solution for 10x^2-12x+4=116 equation:

10x^2-12x+4=116

We move all terms to the left:

10x^2-12x+4-(116)=0

We add all the numbers together, and all the variables

10x^2-12x-112=0

a = 10; b = -12; c = -112;
Δ = b2-4ac
Δ = -122-4·10·(-112)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-68}{2*10}=\frac{-56}{20}
=-2+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+68}{2*10}=\frac{80}{20}
=4
$